X^2+92x-1092=0

Solution for X^2+92x-1092=0 equation:

X^2+92X-1092=0

a = 1; b = 92; c = -1092;
Δ = b2-4ac
Δ = 922-4·1·(-1092)
Δ = 12832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12832}=\sqrt{16*802}=\sqrt{16}*\sqrt{802}=4\sqrt{802}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-4\sqrt{802}}{2*1}=\frac{-92-4\sqrt{802}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+4\sqrt{802}}{2*1}=\frac{-92+4\sqrt{802}}{2}
$